USEFUL MS SQL STATEMENT for Triggers and Constraints

------------

-- Disable all triggers and constraints in a database

------------

USE CopyOfAdventureWorks;

-- SQL disable all triggers

EXEC sp_MSforeachtable @command1="ALTER TABLE ? DISABLE TRIGGER ALL"

GO

-- SQL disable all constraints

EXEC sp_MSforeachtable @command1="ALTER TABLE ? NOCHECK CONSTRAINT ALL"

GO

-- Enable all triggers on a table

ALTER TABLE Production.Product ENABLE TRIGGER ALL

-- Enable all check contraints on a table

ALTER TABLE Production.Product CHECK CONSTRAINT ALL

GO

------------

-- Single constraint disable and enable

------------

USE CopyOfAdventureWorks;

-- SQL disable constraint

ALTER TABLE Production.Product NOCHECK CONSTRAINT CK_Product_DaysToManufacture

GO

-- SQL enable constraint

ALTER TABLE Production.Product CHECK CONSTRAINT CK_Product_DaysToManufacture

GO

-- SQL enable constraint with check of current data

ALTER TABLE Production.Product WITH CHECK

CHECK CONSTRAINT CK_Product_DaysToManufacture

GO

-- SQL enable constraint with no check of current data

ALTER TABLE Production.Product WITH NOCHECK

CHECK CONSTRAINT CK_Product_DaysToManufacture

-- Check integrity of all constraints on a table

DBCC CHECKCONSTRAINTS('Production.Product');

GO

/* DBCC execution completed. If DBCC printed error messages,

contact your system administrator.

*/

------------

------------

-- Single trigger disable and enable

------------

-- SQL disable trigger

ALTER TABLE Sales.SalesOrderHeader DISABLE TRIGGER uSalesOrderHeader

GO

-- SQL enable trigger

ALTER TABLE Sales.SalesOrderHeader ENABLE TRIGGER uSalesOrderHeader

GO

------------

------------

-- Create a check constraint for a table and enable it

------------

-- SQL create check constraint

-- Range constraint - column value must be between 0 and 100

USE AdventureWorks;

ALTER TABLE [Production].[ProductInventory] WITH CHECK

ADD CONSTRAINT [CK_ProductInventory_Bin]

CHECK (([Bin]>=(0) AND [Bin]<=(100)))

GO

-- SQL enable check constraint

ALTER TABLE [Production].[ProductInventory]

CHECK CONSTRAINT [CK_ProductInventory_Bin]

GO

Here is a formula for finding the day of the week for ANY date

Here is a formula for finding the day of the week for ANY date.

 N = d + 2m + [3(m+1)/5] + y + [y/4] - [y/100] + [y/400] + 2

where d is the number or the day of the month, m is the number of the
month, and y is the year. The brackets around the divisions mean to
drop the remainder and just use the integer part that you get.

Also, a VERY IMPORTANT RULE is the number to use for the months for
January and February. The numbers of these months are 13 and 14 of the
PREVIOUS YEAR. This means that to find the day of the week of New
Year's Day this year, 1/1/98, you must use the date 13/1/97. (It
sounds complicated, but I will
do a couple of examples for you.)

After you find the number N, divide it by 7, and the REMAINDER of that
division tells you the day of the week; 1 = Sunday, 2 = Monday, 3 =
Tuesday, etc; BUT, if the remainder is 0, then the day is Saturday,
that is: 0 = Saturday.

As an example, let's check it out on today's date, 3/18/98. Plugging
the numbers into the formula, we get;

 N = 18 + 2(3) + [3(3+1)/5] + 1998 + [1998/4] - [1998/100]
     + [1998/400] + 2

So doing the calculations, (remember to drop the remainder for the
divisions that are in the brackets) we get;

 N = 18 + 6 + 2 + 1998 + 499 - 19 + 4 + 2 = 2510

Now divide 1510 by 7 and you will get 358 with a remainder of 4. Since
4 corresponds to Wednesday, then today must be Wednesday.

You asked about New Year's Day, so let's look at this year, 1/1/98.
Because of the "Very Important Rule," we must use the "date" 13/1/97

to find New Year's Day this year. Plugging into the formula, we get;

 N = 1 + 2(13) + [3(13+1)/5] + 1997 + [1997/4] - [1997/100]
     + [1997/400] + 2

 N = 1+ 26 + 8 + 1997 + 499 - 19 + 4 + 2 = 2518

Now divide 2518 by 7 and look at the remainder: 2518/7 = 359 with a
remainder of 5. Since 5 corresponds to Thursday, New Year's Day this
year was on a Thursday.

Command to run if the asp.net installed before the IIS : Failed to access IIS metabase

Possible Cause:-
When you install IIS AFTER .NET 2.0 framework, the rights of the ASPNET user had not been set correctly.

Resolution
Repair (Uninstall if repair does not work for you) .NET Framework 2.0

Simply run the following from command line to reset the IIS registry settings for aspnet user. Usually framework directory for .Net Framework 2.0 resides under C:\WINDOWS\Microsoft.NET\Framework\v2.0.50727

References:-

• http://support.microsoft.com/?kbid=267904 http://forums.microsoft.com/MSDN/ShowPost.aspx?PostID=116989&SiteID=1
• http://support.microsoft.com/kb/555583

Key in only Numbers in Text Box using Java Script For ASP.Net

//JavaScript Function:

<script language="javascript" type="text/javascript">

function num()

{

if (event.keyCode <> 57) {

event.keycode = 0;

return false;

}

else

return true;

}

script>

//Function Call in text box:
<asp:TextBox ID="TExternalDocumentNo" onkeyPress="return num()" runat="server">asp:TextBox>

Retrieve Records from Excel Using MS SQL

sp_configure

sp_configure 'show advanced options', 1
reconfigure

sp_configure 'Ad Hoc Distributed Queries', 1

reconfigure

sp_configure

SELECT *
FROM OPENROWSET('Microsoft.Jet.OLEDB.4.0',
'Excel 8.0;Database=C:\FPSReport.xls',
'SELECT * FROM [Sheet1$]')

MS SQL Function Execute Expression from String

USE master
Create table EvalRes (expVal real)
go

USE master
Create Function dbo.Eval (@exp varchar(5000))
returns real
as
begin

declare @ans real
declare @osqlStmt varchar(5000)

set @osqlStmt = 'osql.exe -E -q' + '" Insert master..EvalRes select ' + @exp + '"'
exec master..xp_cmdShell @osqlStmt
select @ans = expVal From EvalRes
set @osqlStmt = 'osql.exe -E -q' + '" delete master..EvalRes ' + '"'
exec master..xp_cmdShell @osqlStmt
return @ans
end
go

---example call : select master.dbo.Eval ('((4.5)+5)*6-1-(3*7)+3.512')

If you have any problem in Execute the above script then run the following scripts:

--To enable xp_cmdshell extended stored procedure, you can run the below code as the sa account or another administrator account;
USE master
GO
EXEC sp_configure 'show advanced options', 1
GO
-- Returns the following message after a successfull execution
-- Configuration option 'show advanced options' changed from 0 to 1. Run the RECONFIGURE statement to install.
RECONFIGURE WITH OVERRIDE
GO
EXEC sp_configure 'xp_cmdshell', 1
GO
-- Returns the following message after a successfull execution
-- Configuration option 'xp_cmdshell' changed from 0 to 1. Run the RECONFIGURE statement to install.
RECONFIGURE WITH OVERRIDE
GO
EXEC sp_configure 'show advanced options', 0
GO
-- Returns the following message after a successfull execution
-- Configuration option 'show advanced options' changed from 1 to 0. Run the RECONFIGURE statement to install.
----

MS SQL Date Formating

How to format datetime & date in Sql Server 2005
June 11, 2009 — Anubhav Goyal
Execute the following Microsoft SQL Server T-SQL datetime and date formatting scripts in Management Studio Query Editor to demonstrate the multitude of temporal data formats available in SQL Server.
First we start with the conversion options available for sql datetime formats with century (YYYY or CCYY format). Subtracting 100 from the Style (format) number will transform dates without century (YY). For example Style 103 is with century, Style 3 is without century. The default Style values – Style 0 or 100, 9 or 109, 13 or 113, 20 or 120, and 21 or 121 – always return the century (yyyy) format.

– Microsoft SQL Server T-SQL date and datetime formats
– Date time formats – mssql datetime
– MSSQL getdate returns current system date and time in standard internal format
SELECT convert(varchar, getdate(), 100) – mon dd yyyy hh:mmAM (or PM)
– Oct 2 2008 11 2 2008 11 :01AM
SELECT convert(varchar, getdate(), 101) – mm/dd/yyyy - 10/02/2008
SELECT convert(varchar, getdate(), 102) – yyyy.mm.dd – 2008.10.02
SELECT convert(varchar, getdate(), 103) – dd/mm/yyyy
SELECT convert(varchar, getdate(), 104) – dd.mm.yyyy
SELECT convert(varchar, getdate(), 105) – dd-mm-yyyy
SELECT convert(varchar, getdate(), 106) – dd mon yyyy
SELECT convert(varchar, getdate(), 107) – mon dd, yyyy
SELECT convert(varchar, getdate(), 108) – hh:mm:ss
SELECT convert(varchar, getdate(), 109) – mon dd yyyy hh:mm:ss:mmmAM (or PM)
– Oct 2 2008 11 2 2008 11 :02:44:013AM
SELECT convert(varchar, getdate(), 110) – mm-dd-yyyy
SELECT convert(varchar, getdate(), 111) – yyyy/mm/dd
SELECT convert(varchar, getdate(), 112) – yyyymmdd
SELECT convert(varchar, getdate(), 113) – dd mon yyyy hh:mm:ss:mmm
– 02 Oct 2008 11:02:07:577
SELECT convert(varchar, getdate(), 114) – hh:mm:ss:mmm(24h)
SELECT convert(varchar, getdate(), 120) – yyyy-mm-dd hh:mm:ss(24h)
SELECT convert(varchar, getdate(), 121) – yyyy-mm-dd hh:mm:ss.mmm
SELECT convert(varchar, getdate(), 126) – yyyy-mm-ddThh:mm:ss.mmm
– 2008-10-02T10:52:47.513
– SQL create different date styles with t-sql string functions
SELECT replace(convert(varchar, getdate(), 111), ‘/’, ‘ ‘) – yyyy mm dd
SELECT convert(varchar(7), getdate(), 126) – yyyy-mm
SELECT right(convert(varchar, getdate(), 106), 8) – mon yyyy
————
– SQL Server date formatting function – convert datetime to string
————
– SQL datetime functions
– SQL Server date formats
– T-SQL convert dates
– Formatting dates sql server
CREATE FUNCTION dbo.fnFormatDate (@Datetime DATETIME, @FormatMask VARCHAR(32))
RETURNS VARCHAR(32)
AS
BEGIN
DECLARE @StringDate VARCHAR(32)
SET @StringDate = @FormatMask
IF (CHARINDEX (‘YYYY’,@StringDate) > 0)
SET @StringDate = REPLACE(@StringDate, ‘YYYY’,
DATENAME(YY, @Datetime))
IF (CHARINDEX (‘YY’,@StringDate) > 0)
SET @StringDate = REPLACE(@StringDate, ‘YY’,
RIGHT(DATENAME(YY, @Datetime),2))
IF (CHARINDEX (‘Month’,@StringDate) > 0)
SET @StringDate = REPLACE(@StringDate, ‘Month’,
DATENAME(MM, @Datetime))
IF (CHARINDEX (‘MON’,@StringDate COLLATE SQL_Latin1_General_CP1_CS_AS)>0)
SET @StringDate = REPLACE(@StringDate, ‘MON’,
LEFT(UPPER(DATENAME(MM, @Datetime)),3))
IF (CHARINDEX (‘Mon’,@StringDate) > 0)
SET @StringDate = REPLACE(@StringDate, ‘Mon’,
LEFT(DATENAME(MM, @Datetime),3))
IF (CHARINDEX (‘MM’,@StringDate) > 0)
SET @StringDate = REPLACE(@StringDate, ‘MM’,
RIGHT(’0′+CONVERT(VARCHAR,DATEPART(MM, @Datetime)),2))
IF (CHARINDEX (‘M’,@StringDate) > 0)
SET @StringDate = REPLACE(@StringDate, ‘M’,
CONVERT(VARCHAR,DATEPART(MM, @Datetime)))
IF (CHARINDEX (‘DD’,@StringDate) > 0)
SET @StringDate = REPLACE(@StringDate, ‘DD’,
RIGHT(’0′+DATENAME(DD, @Datetime),2))
IF (CHARINDEX (‘D’,@StringDate) > 0)
SET @StringDate = REPLACE(@StringDate, ‘D’,
DATENAME(DD, @Datetime))
RETURN @StringDate
END
GO

– Microsoft SQL Server date format function test
– MSSQL formatting dates
SELECT dbo.fnFormatDate (getdate(), ‘MM/DD/YYYY’) – 01/03/2012
SELECT dbo.fnFormatDate (getdate(), ‘DD/MM/YYYY’) – 03/01/2012
SELECT dbo.fnFormatDate (getdate(), ‘M/DD/YYYY’) – 1/03/2012
SELECT dbo.fnFormatDate (getdate(), ‘M/D/YYYY’) – 1/3/2012
SELECT dbo.fnFormatDate (getdate(), ‘M/D/YY’) – 1/3/12
SELECT dbo.fnFormatDate (getdate(), ‘MM/DD/YY’) – 01/03/12
SELECT dbo.fnFormatDate (getdate(), ‘MON DD, YYYY’) – JAN 03, 2012
SELECT dbo.fnFormatDate (getdate(), ‘Mon DD, YYYY’) – Jan 03, 2012
SELECT dbo.fnFormatDate (getdate(), ‘Month DD, YYYY’) – January 03, 2012
SELECT dbo.fnFormatDate (getdate(), ‘YYYY/MM/DD’) – 2012/01/03
SELECT dbo.fnFormatDate (getdate(), ‘YYYYMMDD’) – 20120103
SELECT dbo.fnFormatDate (getdate(), ‘YYYY-MM-DD’) – 2012-01-03
– CURRENT_TIMESTAMP returns current system date and time in standard internal format
SELECT dbo.fnFormatDate (CURRENT_TIMESTAMP,‘YY.MM.DD’) – 12.01.03
GO
————

/***** SELECTED SQL DATE/DATETIME FORMATS WITH NAMES *****/

– SQL format datetime
– Default format: Oct 23 2006 10 23 2006 10 :40AM
SELECT [Default]=CONVERT(varchar,GETDATE(),100)

– US-Style format: 10/23/2006
SELECT [US-Style]=CONVERT(char,GETDATE(),101)

– ANSI format: 2006.10.23
SELECT [ANSI]=CONVERT(char,CURRENT_TIMESTAMP,102)

– UK-Style format: 23/10/2006
SELECT [UK-Style]=CONVERT(char,GETDATE(),103)

– German format: 23.10.2006
SELECT [German]=CONVERT(varchar,GETDATE(),104)

– ISO format: 20061023
SELECT ISO=CONVERT(varchar,GETDATE(),112)

– ISO8601 format: 2008-10-23T19:20:16.003
SELECT [ISO8601]=CONVERT(varchar,GETDATE(),126)
————

– SQL Server datetime formats
– Century date format MM/DD/YYYY usage in a query
– Format dates SQL Server 2005
SELECT TOP (1)
SalesOrderID,
OrderDate = CONVERT(char(10), OrderDate, 101),
OrderDateTime = OrderDate
FROM AdventureWorks.Sales.SalesOrderHeader
/* Result

SalesOrderID OrderDate OrderDateTime
43697 07/01/2001 2001-07-01 00:00:00.000
*/

– SQL update datetime column
– SQL datetime DATEADD
UPDATE Production.Product
SET ModifiedDate=DATEADD(dd,1, ModifiedDate)
WHERE ProductID = 1001

– MM/DD/YY date format
– Datetime format sql
SELECT TOP (1)
SalesOrderID,
OrderDate = CONVERT(varchar(8), OrderDate, 1),
OrderDateTime = OrderDate
FROM AdventureWorks.Sales.SalesOrderHeader
ORDER BY SalesOrderID desc
/* Result

SalesOrderID OrderDate OrderDateTime
75123 07/31/04 2004-07-31 00:00:00.000
*/

– Combining different style formats for date & time
– Datetime formats
– Datetime formats sql
DECLARE @Date DATETIME
SET @Date = ’2015-12-22 03:51 PM’
SELECT CONVERT(CHAR(10),@Date,110) + SUBSTRING(CONVERT(varchar,@Date,0),12,8)
– Result: 12-22-2015 3:51PM

– Microsoft SQL Server cast datetime to string
SELECT stringDateTime=CAST (getdate() as varchar)
– Result: Dec 29 2012 3:47AM
————
– SQL Server date and time functions overview
————
– SQL Server CURRENT_TIMESTAMP function
– SQL Server datetime functions
– local NYC – EST – Eastern Standard Time zone
– SQL DATEADD function – SQL DATEDIFF function
SELECT CURRENT_TIMESTAMP – 2012-01-05 07:02:10.577
– SQL Server DATEADD function
SELECT DATEADD(month,2,’2012-12-09′) – 2013-02-09 00:00:00.000
– SQL Server DATEDIFF function
SELECT DATEDIFF(day,’2012-12-09′,’2013-02-09′) – 62
– SQL Server DATENAME function
SELECT DATENAME(month, ’2012-12-09′) – December
SELECT DATENAME(weekday, ’2012-12-09′) – Sunday
– SQL Server DATEPART function
SELECT DATEPART(month, ’2012-12-09′) – 12
– SQL Server DAY function
SELECT DAY(’2012-12-09′) – 9
– SQL Server GETDATE function
– local NYC – EST – Eastern Standard Time zone
SELECT GETDATE() – 2012-01-05 07:02:10.577
– SQL Server GETUTCDATE function
– London – Greenwich Mean Time
SELECT GETUTCDATE() – 2012-01-05 12:02:10.577
– SQL Server MONTH function
SELECT MONTH(’2012-12-09′) – 12
– SQL Server YEAR function
SELECT YEAR(’2012-12-09′) – 2012


————
– T-SQL Date and time function application
– CURRENT_TIMESTAMP and getdate() are the same in T-SQL
————
– SQL first day of the month
– SQL first date of the month
– SQL first day of current month – 2012-01-01 00:00:00.000
SELECT DATEADD(dd,0,DATEADD(mm, DATEDIFF(mm,0,CURRENT_TIMESTAMP),0))
– SQL last day of the month
– SQL last date of the month
– SQL last day of current month – 2012-01-31 00:00:00.000
SELECT DATEADD(dd,-1,DATEADD(mm, DATEDIFF(mm,0,CURRENT_TIMESTAMP)+1,0))
– SQL first day of last month
– SQL first day of previous month – 2011-12-01 00:00:00.000
SELECT DATEADD(mm,-1,DATEADD(mm, DATEDIFF(mm,0,CURRENT_TIMESTAMP),0))
– SQL last day of last month
– SQL last day of previous month – 2011-12-31 00:00:00.000
SELECT DATEADD(dd,-1,DATEADD(mm, DATEDIFF(mm,0,DATEADD(MM,-1,GETDATE()))+1,0))
– SQL first day of next month – 2012-02-01 00:00:00.000
SELECT DATEADD(mm,1,DATEADD(mm, DATEDIFF(mm,0,CURRENT_TIMESTAMP),0))
– SQL last day of next month – 2012-02-28 00:00:00.000
SELECT DATEADD(dd,-1,DATEADD(mm, DATEDIFF(mm,0,DATEADD(MM,1,GETDATE()))+1,0))
GO
– SQL first day of a month – 2012-10-01 00:00:00.000
DECLARE @Date datetime; SET @Date = ’2012-10-23′
SELECT DATEADD(dd,0,DATEADD(mm, DATEDIFF(mm,0,@Date),0))
GO
– SQL last day of a month – 2012-03-31 00:00:00.000
DECLARE @Date datetime; SET @Date = ’2012-03-15′
SELECT DATEADD(dd,-1,DATEADD(mm, DATEDIFF(mm,0,@Date)+1,0))
GO
– SQL first day of year
– SQL first day of the year - 2012-01-01 00:00:00.000
SELECT DATEADD(yy, DATEDIFF(yy,0,CURRENT_TIMESTAMP), 0)
– SQL last day of year
– SQL last day of the year – 2012-12-31 00:00:00.000
SELECT DATEADD(yy,1, DATEADD(dd, -1, DATEADD(yy,
DATEDIFF(yy,0,CURRENT_TIMESTAMP), 0)))
– SQL last day of last year
– SQL last day of previous year – 2011-12-31 00:00:00.000
SELECT DATEADD(dd,-1,DATEADD(yy,DATEDIFF(yy,0,CURRENT_TIMESTAMP), 0))
GO
– SQL calculate age in years, months, days
– SQL table-valued function
– SQL user-defined function – UDF
– SQL Server age calculation – date difference
– Format dates SQL Server 2008
USE AdventureWorks2008;
GO
CREATE FUNCTION fnAge (@BirthDate DATETIME)
RETURNS @Age TABLE(Years INT,
Months INT,
Days INT)
AS
BEGIN
DECLARE @EndDate DATETIME, @Anniversary DATETIME
SET @EndDate = Getdate()
SET @Anniversary = Dateadd(yy,Datediff(yy,@BirthDate,@EndDate),@BirthDate)

INSERT @Age
SELECT Datediff(yy,@BirthDate,@EndDate) - (CASE
WHEN @Anniversary > @EndDate THEN 1
ELSE 0
END), 0, 0
UPDATE @Age SET Months = Month(@EndDate - @Anniversary) - 1
UPDATE @Age SET Days = Day(@EndDate - @Anniversary) - 1
RETURN
END
GO

– Test table-valued UDF
SELECT * FROM fnAge(’1956-10-23′)
SELECT * FROM dbo.fnAge(’1956-10-23′)
/* Results
Years Months Days
52 4 1
*/

———-
– SQL date range between
———-
– SQL between dates
USE AdventureWorks;
– SQL between
SELECT POs=COUNT(*) FROM Purchasing.PurchaseOrderHeader
WHERE OrderDate BETWEEN ’20040301′ AND ’20040315′
– Result: 108

– BETWEEN operator is equivalent to >=…AND….<=
SELECT POs=COUNT(*) FROM Purchasing.PurchaseOrderHeader
WHERE OrderDate
BETWEEN ’2004-03-01 00:00:00.000′ AND ’2004-03-15 00:00:00.000′
/*
Orders with OrderDates
’2004-03-15 00:00:01.000′ – 1 second after midnight (12:00AM)
’2004-03-15 00:01:00.000′ – 1 minute after midnight
’2004-03-15 01:00:00.000′ – 1 hour after midnight

are not included in the two queries above.
*/
– To include the entire day of 2004-03-15 use the following two solutions
SELECT POs=COUNT(*) FROM Purchasing.PurchaseOrderHeader
WHERE OrderDate >= ’20040301′ AND OrderDate < ’20040316′

– SQL between with DATE type (SQL Server 2008)
SELECT POs=COUNT(*) FROM Purchasing.PurchaseOrderHeader
WHERE CONVERT(DATE, OrderDate) BETWEEN ’20040301′ AND ’20040315′
———-
– Non-standard format conversion: 2011 December 14
– SQL datetime to string
SELECT [YYYY Month DD] =
CAST(YEAR(GETDATE()) AS VARCHAR(4))+ ‘ ‘+
DATENAME(MM, GETDATE()) + ‘ ‘ +
CAST(DAY(GETDATE()) AS VARCHAR(2))

– Converting datetime to YYYYMMDDHHMMSS format: 20121214172638
SELECT replace(convert(varchar, getdate(),111),‘/’,”) +
replace(convert(varchar, getdate(),108),‘:’,”)

– Datetime custom format conversion to YYYY_MM_DD
select CurrentDate=rtrim(year(getdate())) + ‘_’ +
right(’0′ + rtrim(month(getdate())),2) + ‘_’ +
right(’0′ + rtrim(day(getdate())),2)

– Converting seconds to HH:MM:SS format
declare @Seconds int
set @Seconds = 10000
select TimeSpan=right(’0′ +rtrim(@Seconds / 3600),2) + ‘:’ +
right(’0′ + rtrim((@Seconds % 3600) / 60),2) + ‘:’ +
right(’0′ + rtrim(@Seconds % 60),2)
– Result: 02:46:40

– Test result
select 2*3600 + 46*60 + 40
– Result: 10000
– Set the time portion of a datetime value to 00:00:00.000
– SQL strip time from date
– SQL strip time from datetime
SELECT CURRENT_TIMESTAMP ,DATEADD(dd, DATEDIFF(dd, 0, CURRENT_TIMESTAMP), 0)
– Results: 2014-01-23 05:35:52.793 2014-01-23 00:00:00.000
/*******

VALID DATE RANGES FOR DATE/DATETIME DATA TYPES

SMALLDATETIME date range:
January 1, 1900 through June 6, 2079

DATETIME date range:
January 1, 1753 through December 31, 9999

DATETIME2 date range (SQL Server 2008):
January 1,1 AD through December 31, 9999 AD

DATE date range (SQL Server 2008):
January 1, 1 AD through December 31, 9999 AD

*******/
– Selecting with CONVERT into different styles
– Note: Only Japan & ISO styles can be used in ORDER BY
SELECT TOP(1)
Italy = CONVERT(varchar, OrderDate, 105)
, USA = CONVERT(varchar, OrderDate, 110)
, Japan = CONVERT(varchar, OrderDate, 111)
, ISO = CONVERT(varchar, OrderDate, 112)
FROM AdventureWorks.Purchasing.PurchaseOrderHeader
ORDER BY PurchaseOrderID DESC
/* Results
Italy USA Japan ISO
25-07-2004 07-25-2004 2004/07/25 20040725
*/
– SQL Server convert date to integer
DECLARE @Datetime datetime
SET @Datetime = ’2012-10-23 10:21:05.345′
SELECT DateAsInteger = CAST (CONVERT(varchar,@Datetime,112) as INT)
– Result: 20121023

– SQL Server convert integer to datetime
DECLARE @intDate int
SET @intDate = 20120315
SELECT IntegerToDatetime = CAST(CAST(@intDate as varchar) as datetime)
– Result: 2012-03-15 00:00:00.000
————
– SQL Server CONVERT script applying table INSERT/UPDATE
————
– SQL Server convert date
– Datetime column is converted into date only string column
USE tempdb;
GO
CREATE TABLE sqlConvertDateTime (
DatetimeCol datetime,
DateCol char(8));
INSERT sqlConvertDateTime (DatetimeCol) SELECT GETDATE()

UPDATE sqlConvertDateTime
SET DateCol = CONVERT(char(10), DatetimeCol, 112)
SELECT * FROM sqlConvertDateTime

– SQL Server convert datetime
– The string date column is converted into datetime column
UPDATE sqlConvertDateTime
SET DatetimeCol = CONVERT(Datetime, DateCol, 112)
SELECT * FROM sqlConvertDateTime

– Adding a day to the converted datetime column with DATEADD
UPDATE sqlConvertDateTime
SET DatetimeCol = DATEADD(day, 1, CONVERT(Datetime, DateCol, 112))
SELECT * FROM sqlConvertDateTime

– Equivalent formulation
– SQL Server cast datetime
UPDATE sqlConvertDateTime
SET DatetimeCol = DATEADD(dd, 1, CAST(DateCol AS datetime))
SELECT * FROM sqlConvertDateTime
GO
DROP TABLE sqlConvertDateTime
GO
/* First results
DatetimeCol DateCol
2014-12-25 16:04:15.373 20141225 */

/* Second results:
DatetimeCol DateCol
2014-12-25 00:00:00.000 20141225 */

/* Third results:
DatetimeCol DateCol
2014-12-26 00:00:00.000 20141225 */
————
– SQL month sequence – SQL date sequence generation with table variable
– SQL Server cast string to datetime – SQL Server cast datetime to string
– SQL Server insert default values method
DECLARE @Sequence table (Sequence int identity(1,1))
DECLARE @i int; SET @i = 0
DECLARE @StartDate datetime;
SET @StartDate = CAST(CONVERT(varchar, year(getdate()))+
RIGHT(’0′+convert(varchar,month(getdate())),2) + ’01′ AS DATETIME)
WHILE ( @i < 120)
BEGIN
INSERT @Sequence DEFAULT VALUES
SET @i = @i + 1
END
SELECT MonthSequence = CAST(DATEADD(month, Sequence,@StartDate) AS varchar)
FROM @Sequence
GO
/* Partial results:
MonthSequence
Jan 1 2012 12:00AM
Feb 1 2012 12:00AM
Mar 1 2012 12:00AM
Apr 1 2012 12:00AM
*/
————

————
– SQL Server Server datetime internal storage
– SQL Server datetime formats
————
– SQL Server datetime to hex
SELECT Now=CURRENT_TIMESTAMP, HexNow=CAST(CURRENT_TIMESTAMP AS BINARY(8))
/* Results

Now HexNow
2009-01-02 17:35:59.297 0x00009B850122092D
*/
– SQL Server date part – left 4 bytes – Days since 1900-01-01
SELECT Now=DATEADD(DAY, CONVERT(INT, 0x00009B85), ’19000101′)
GO
– Result: 2009-01-02 00:00:00.000

– SQL time part – right 4 bytes – milliseconds since midnight
– 1000/300 is an adjustment factor
– SQL dateadd to Midnight
SELECT Now=DATEADD(MS, (1000.0/300)* CONVERT(BIGINT, 0x0122092D), ’2009-01-02′)
GO
– Result: 2009-01-02 17:35:59.290
————
————
– String date and datetime date&time columns usage
– SQL Server datetime formats in tables
————
USE tempdb;
SET NOCOUNT ON;
– SQL Server select into table create
SELECT TOP (5)
FullName=convert(nvarchar(50),FirstName+‘ ‘+LastName),
BirthDate = CONVERT(char(8), BirthDate,112),
ModifiedDate = getdate()
INTO Employee
FROM AdventureWorks.HumanResources.Employee e
INNER JOIN AdventureWorks.Person.Contact c
ON c.ContactID = e.ContactID
ORDER BY EmployeeID
GO
– SQL Server alter table
ALTER TABLE Employee ALTER COLUMN FullName nvarchar(50) NOT NULL
GO
ALTER TABLE Employee
ADD CONSTRAINT [PK_Employee] PRIMARY KEY (FullName )
GO
/* Results

Table definition for the Employee table
Note: BirthDate is string date (only)

CREATE TABLE dbo.Employee(
FullName nvarchar(50) NOT NULL PRIMARY KEY,
BirthDate char(8) NULL,
ModifiedDate datetime NOT NULL
)
*/
SELECT * FROM Employee ORDER BY FullName
GO
/* Results
FullName BirthDate ModifiedDate
Guy Gilbert 19720515 2009-01-03 10:10:19.217
Kevin Brown 19770603 2009-01-03 10:10:19.217
Rob Walters 19650123 2009-01-03 10:10:19.217
Roberto Tamburello 19641213 2009-01-03 10:10:19.217
Thierry D’Hers 19490829 2009-01-03 10:10:19.217
*/

– SQL Server age
SELECT FullName, Age = DATEDIFF(YEAR, BirthDate, GETDATE()),
RowMaintenanceDate = CAST (ModifiedDate AS varchar)
FROM Employee ORDER BY FullName
GO
/* Results
FullName Age RowMaintenanceDate
Guy Gilbert 37 Jan 3 2009 10:10AM
Kevin Brown 32 Jan 3 2009 10:10AM
Rob Walters 44 Jan 3 2009 10:10AM
Roberto Tamburello 45 Jan 3 2009 10:10AM
Thierry D’Hers 60 Jan 3 2009 10:10AM
*/

– SQL Server age of Rob Walters on specific dates
– SQL Server string to datetime implicit conversion with DATEADD
SELECT AGE50DATE = DATEADD(YY, 50, ’19650123′)
GO
– Result: 2015-01-23 00:00:00.000

– SQL Server datetime to string, Italian format for ModifiedDate
– SQL Server string to datetime implicit conversion with DATEDIFF
SELECT FullName,
AgeDEC31 = DATEDIFF(YEAR, BirthDate, ’20141231′),
AgeJAN01 = DATEDIFF(YEAR, BirthDate, ’20150101′),
AgeJAN23 = DATEDIFF(YEAR, BirthDate, ’20150123′),
AgeJAN24 = DATEDIFF(YEAR, BirthDate, ’20150124′),
ModDate = CONVERT(varchar, ModifiedDate, 105)
FROM Employee
WHERE FullName = ‘Rob Walters’
ORDER BY FullName
GO
/* Results
Important Note: age increments on Jan 1 (not as commonly calculated)

FullName AgeDEC31 AgeJAN01 AgeJAN23 AgeJAN24 ModDate
Rob Walters 49 50 50 50 03-01-2009
*/

————
– SQL combine integer date & time into datetime
————
– Datetime format sql
– SQL stuff
DECLARE @DateTimeAsINT TABLE ( ID int identity(1,1) primary key,
DateAsINT int,
TimeAsINT int
)
– NOTE: leading zeroes in time is for readability only!
INSERT @DateTimeAsINT (DateAsINT, TimeAsINT) VALUES (20121023, 235959)
INSERT @DateTimeAsINT (DateAsINT, TimeAsINT) VALUES (20121023, 010204)
INSERT @DateTimeAsINT (DateAsINT, TimeAsINT) VALUES (20121023, 002350)
INSERT @DateTimeAsINT (DateAsINT, TimeAsINT) VALUES (20121023, 000244)
INSERT @DateTimeAsINT (DateAsINT, TimeAsINT) VALUES (20121023, 000050)
INSERT @DateTimeAsINT (DateAsINT, TimeAsINT) VALUES (20121023, 000006)

SELECT DateAsINT, TimeAsINT,
CONVERT(datetime, CONVERT(varchar(8), DateAsINT) + ‘ ‘+
STUFF(STUFF ( RIGHT(REPLICATE(’0′, 6) + CONVERT(varchar(6), TimeAsINT), 6),
3, 0, ‘:’), 6, 0, ‘:’)) AS DateTimeValue
FROM @DateTimeAsINT
ORDER BY ID
GO
/* Results
DateAsINT TimeAsINT DateTimeValue
20121023 235959 2012-10-23 23:59:59.000
20121023 10204 2012-10-23 01:02:04.000
20121023 2350 2012-10-23 00:23:50.000
20121023 244 2012-10-23 00:02:44.000
20121023 50 2012-10-23 00:00:50.000
20121023 6 2012-10-23 00:00:06.000
*/
————

– SQL Server string to datetime, implicit conversion with assignment
UPDATE Employee SET ModifiedDate = ’20150123′
WHERE FullName = ‘Rob Walters’
GO
SELECT ModifiedDate FROM Employee WHERE FullName = ‘Rob Walters’
GO
– Result: 2015-01-23 00:00:00.000

/* SQL string date, assemble string date from datetime parts */
– SQL Server cast string to datetime – sql convert string date
– SQL Server number to varchar conversion
– SQL Server leading zeroes for month and day
– SQL Server right string function
UPDATE Employee SET BirthDate =
CONVERT(char(4),YEAR(CAST(’1965-01-23′ as DATETIME)))+
RIGHT(’0′+CONVERT(varchar,MONTH(CAST(’1965-01-23′ as DATETIME))),2)+
RIGHT(’0′+CONVERT(varchar,DAY(CAST(’1965-01-23′ as DATETIME))),2)
WHERE FullName = ‘Rob Walters’
GO
SELECT BirthDate FROM Employee WHERE FullName = ‘Rob Walters’
GO
– Result: 19650123

– Perform cleanup action
DROP TABLE Employee
– SQL nocount
SET NOCOUNT OFF;
GO
————
————
– sql isdate function
————
USE tempdb;
– sql newid – random sort
SELECT top(3) SalesOrderID,
stringOrderDate = CAST (OrderDate AS varchar)
INTO DateValidation
FROM AdventureWorks.Sales.SalesOrderHeader
ORDER BY NEWID()
GO
SELECT * FROM DateValidation
/* Results
SalesOrderID stringOrderDate
56720 Oct 26 2003 12 26 2003 12 :00AM
73737 Jun 25 2004 12 25 2004 12 :00AM
70573 May 14 2004 12:00AM
*/
– SQL update with top
UPDATE TOP(1) DateValidation
SET stringOrderDate = ‘Apb 29 2004 12 29 2004 12 :00AM’
GO
– SQL string to datetime fails without validation
SELECT SalesOrderID, OrderDate = CAST (stringOrderDate as datetime)
FROM DateValidation
GO
/* Msg 242, Level 16, State 3, Line 1
The conversion of a varchar data type to a datetime data type resulted in an
out-of-range value.
*/
– sql isdate – filter for valid dates
SELECT SalesOrderID, OrderDate = CAST (stringOrderDate as datetime)
FROM DateValidation
WHERE ISDATE(stringOrderDate) = 1
GO
/* Results
SalesOrderID OrderDate
73737 2004-06-25 00:00:00.000
70573 2004-05-14 00:00:00.000
*/
– SQL drop table
DROP TABLE DateValidation
Go

————
– SELECT between two specified dates – assumption TIME part is 00:00:00.000
————
– SQL datetime between
– SQL select between two dates
SELECT EmployeeID, RateChangeDate
FROM AdventureWorks.HumanResources.EmployeePayHistory
WHERE RateChangeDate >= ’1997-11-01′ AND
RateChangeDate < DATEADD(dd,1,’1998-01-05′)
GO
/* Results
EmployeeID RateChangeDate
3 1997-12-12 00:00:00.000
4 1998-01-05 00:00:00.000
*/

/* Equivalent to

– SQL datetime range
SELECT EmployeeID, RateChangeDate
FROM AdventureWorks.HumanResources.EmployeePayHistory
WHERE RateChangeDate >= ’1997-11-01 00:00:00′ AND
RateChangeDate < ’1998-01-06 00:00:00′
GO
*/
————
– SQL datetime language setting
– SQL Nondeterministic function usage – result varies with language settings
SET LANGUAGE ‘us_english’; –– Jan 12 2015 12:00AM
SELECT US = convert(VARCHAR,convert(DATETIME,’01/12/2015′));
SET LANGUAGE ‘British’; –– Dec 1 2015 12:00AM
SELECT UK = convert(VARCHAR,convert(DATETIME,’01/12/2015′));
SET LANGUAGE ‘German’; –– Dez 1 2015 12:00AM
SET LANGUAGE ‘Deutsch’; –– Dez 1 2015 12:00AM
SELECT Germany = convert(VARCHAR,convert(DATETIME,’01/12/2015′));
SET LANGUAGE ‘French’; –– déc 1 2015 12:00AM
SELECT France = convert(VARCHAR,convert(DATETIME,’01/12/2015′));
SET LANGUAGE ‘Spanish’; –– Dic 1 2015 12:00AM
SELECT Spain = convert(VARCHAR,convert(DATETIME,’01/12/2015′));
SET LANGUAGE ‘Hungarian’; –– jan 12 2015 12:00AM
SELECT Hungary = convert(VARCHAR,convert(DATETIME,’01/12/2015′));
SET LANGUAGE ‘us_english’;
GO
————
————
– Function for Monday dates calculation
————
USE AdventureWorks2008;
GO
– SQL user-defined function
– SQL scalar function – UDF
CREATE FUNCTION fnMondayDate
(@Year INT,
@Month INT,
@MondayOrdinal INT)
RETURNS DATETIME
AS
BEGIN
DECLARE @FirstDayOfMonth CHAR(10),
@SeedDate CHAR(10)

SET @FirstDayOfMonth = convert(VARCHAR,@Year) + ‘-’ + convert(VARCHAR,@Month) + ‘-01′
SET @SeedDate = ’1900-01-01′

RETURN DATEADD(DD,DATEDIFF(DD,@SeedDate,DATEADD(DD,(@MondayOrdinal * 7) - 1,
@FirstDayOfMonth)) / 7 * 7, @SeedDate)
END
GO

– Test Datetime UDF
– Third Monday in Feb, 2015
SELECT dbo.fnMondayDate(2016,2,3)
– 2015-02-16 00:00:00.000

– First Monday of current month
SELECT dbo.fnMondayDate(Year(getdate()),Month(getdate()),1)
– 2009-02-02 00:00:00.000

MS SQL Function for Convert Number to Word

-- SQL number to words - SQL number to English - convert numbers into words

-- Translate number to text - Translate number to English - SQL number to check printing


-- SQL user-defined function - UDF - SQL scalar-valued function - SQL number to text

-- SQL numeric to words - integer to English - sql convert number to string
CREATE FUNCTION fnNumberToWords(@Number as BIGINT)
RETURNS VARCHAR(1024)
AS
BEGIN
DECLARE @Below20 TABLE (ID int identity(0,1), Word varchar(32))
DECLARE @Below100 TABLE (ID int identity(2,1), Word varchar(32))
DECLARE @English varchar(1024)
INSERT @Below20 (Word) VALUES ( 'Zero')
INSERT @Below20 (Word) VALUES ('One')
INSERT @Below20 (Word) VALUES ( 'Two' )
INSERT @Below20 (Word) VALUES ( 'Three')
INSERT @Below20 (Word) VALUES ( 'Four' )
INSERT @Below20 (Word) VALUES ( 'Five' )
INSERT @Below20 (Word) VALUES ( 'Six' )
INSERT @Below20 (Word) VALUES ( 'Seven' )
INSERT @Below20 (Word) VALUES ('Eight')
INSERT @Below20 (Word) VALUES ( 'Nine')
INSERT @Below20 (Word) VALUES ( 'Ten')
INSERT @Below20 (Word) VALUES ( 'Eleven' )
INSERT @Below20 (Word) VALUES ( 'Twelve' )
INSERT @Below20 (Word) VALUES ( 'Thirteen' )
INSERT @Below20 (Word) VALUES ( 'Fourteen')
INSERT @Below20 (Word) VALUES ( 'Fifteen' )
INSERT @Below20 (Word) VALUES ('Sixteen' )
INSERT @Below20 (Word) VALUES ( 'Seventeen')
INSERT @Below20 (Word) VALUES ('Eighteen' )
INSERT @Below20 (Word) VALUES ( 'Nineteen' )

INSERT @Below100 VALUES ('Twenty')
INSERT @Below100 VALUES ('Thirty')
INSERT @Below100 VALUES ('Forty')
INSERT @Below100 VALUES ('Fifty')
INSERT @Below100 VALUES ('Sixty')
INSERT @Below100 VALUES ('Seventy')
INSERT @Below100 VALUES ('Eighty')
INSERT @Below100 VALUES ('Ninety')
set @English = ( SELECT Case WHEN @Number = 0 THEN ''
WHEN @Number BETWEEN 1 AND 19
THEN (SELECT Word FROM @Below20 WHERE ID=@Number)
WHEN @Number BETWEEN 20 AND 99
THEN (SELECT Word FROM @Below100 WHERE ID=@Number/10)+ '-' +
dbo.fnNumberToWords( @Number % 10)
WHEN @Number BETWEEN 100 AND 999
THEN (dbo.fnNumberToWords( @Number / 100))+' Hundred '+
dbo.fnNumberToWords( @Number % 100)
WHEN @Number BETWEEN 1000 AND 999999
THEN (dbo.fnNumberToWords( @Number / 1000))+' Thousand '+
dbo.fnNumberToWords( @Number % 1000)
WHEN @Number BETWEEN 1000000 AND 999999999
THEN (dbo.fnNumberToWords( @Number / 1000000))+' Million '+
dbo.fnNumberToWords( @Number % 1000000)
WHEN @Number BETWEEN 1000000000 AND 999999999999
THEN (dbo.fnNumberToWords( @Number / 1000000000))+' Billion '+
dbo.fnNumberToWords( @Number % 1000000000)
WHEN @Number BETWEEN 1000000000000 AND 999999999999999
THEN (dbo.fnNumberToWords( @Number / 1000000000000))+' Trillion '+
dbo.fnNumberToWords( @Number % 1000000000000)
WHEN @Number BETWEEN 1000000000000000 AND 999999999999999999
THEN (dbo.fnNumberToWords( @Number / 1000000000000000))+' Quadrillion '+
dbo.fnNumberToWords( @Number % 1000000000000000)
WHEN @Number BETWEEN 1000000000000000000 AND 999999999999999999999
THEN (dbo.fnNumberToWords( @Number / 1000000000000000000))+' Quintillion '+
dbo.fnNumberToWords( @Number % 1000000000000000000)
ELSE ' INVALID INPUT' END
)

SELECT @English = RTRIM(@English)
SELECT @English = RTRIM(LEFT(@English,len(@English)-1))
WHERE RIGHT(@English,1)='-'
RETURN (@English)
END

GO



-- Test number to English translation

SELECT NumberInEnglish=dbo.fnNumberToWords ( 18)

SELECT NumberInEnglish=dbo.fnNumberToWords ( 67)

SELECT NumberInEnglish=dbo.fnNumberToWords ( 947)

-- Nine Hundred Forty-Seven

SELECT NumberInEnglish=dbo.fnNumberToWords ( 984261)

-- Nine Hundred Eighty-Four Thousand Two Hundred Sixty-One

SELECT NumberInEnglish=dbo.fnNumberToWords ( 777999888)

/* Seven Hundred Seventy-Seven Million Nine Hundred Ninety-Nine Thousand

Eight Hundred Eighty-Eight */

SELECT NumberInEnglish=dbo.fnNumberToWords ( 222777999888)

SELECT NumberInEnglish=dbo.fnNumberToWords ( 555222777999888)

SELECT NumberInEnglish=dbo.fnNumberToWords ( 7446744073709551616)

/*

Seven Quintillion Four Hundred Forty-Six Quadrillion Seven Hundred

Forty-Four Trillion Seventy-Three Billion Seven Hundred Nine Million

Five Hundred Fifty-One Thousand Six Hundred Sixteen

*/

GO